Log negative one zero

Theorem: log(-1) = 0
Proof:
a. log[(-1)^2] = 2 * log(-1)

On the other hand:
b. log[(-1)^2] = log(1) = 0

Combining a) and b) gives:
2* log(-1) = 0
Divide both sides by 2:
log(-1) = 0

Related Jokes:

  1. Equal positive integers
  2. Dollars equal ten cents
  3. One plus one are two
  4. Four is equal to five
  5. Proof E equal to one

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